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So, this is Column 1, 2, and part of Column 3 of Cipher 1 in the order as given in the online Library of Congress Version of the Beale Papers pamphlet (Or the 1st 7 sentences):

Plain text reads: "Need the net ready the Tr 500th(x) 2Enter(x) Y note due the one 2 the ER 9 Dr O tho deed 2 Ed Orr 500th to 2 Ed Wire Radeo(x) 8th T(x) e-th(x) Ned Wyte died Y(x) T died the dedth the Ed Roth NE told O die ready o 500 ND(x) . . ."

The 5 Rules for the Beale Cipher 1:

  1. NO BOOK is needed.
  2. There seems to be NO TREASURE in this part -- just the movement of American Civil War Troops and report of their dead.
  3. Columns are READ VERTICALLY, keeping the numbers in their original columns.
  4. The LAST LETTER of each number as spelled out in English is all that is needed.
  5. There are NO ANAGRAMS.

Helpful Beale Cipher Particulars:

  1. Besides being itself and standing for "Y" as in branch or just sounded out (ex: "YTE"="White") , "Y" mostly stand for "Th" (so think of "Ye"="The" as in "Ye Old Bookstore".)
  2. INCLUDE the "D" in "hundreD" or "thousanD" when reading number like "1121"(=onE hundreD onE thousanD twentY onE).
  3. Do NOT include "anD" when reading numbers like "1121".
  4. At times a number like "71" may be read "seveN-onE"(=ex: "NorthEast") as opposed to "71"="seventY-onE"="YE"="The"
  5. The number (siX) is used as a STOP (x) unless it is in the "60" position.
  6. "zerO" is an option.

The first batch of numbers, divided by their columns (///):

  • 71,975,758, 401, 918, 436, 39, 18, 346, 872, 8, 102, 55, 275, 919, 81, 921, 14, 17, 121, 10, 540, 39, 230, 1300, 324, 428, 202 ///
  • 194, 14, 485, 370, 263 65, 88, 64,12, 36, 15, 120, 38, 131, 346, 861, 360, 1060, 23, 340, 67, 98, 232, 261, 460,1706, 403, 601, 35 ///
  • 38, 40, 604 . . . ///

Here is what I got for just raw text: "NEED YE NET-RDE YET RD Y(x)E ENTER(x)Y NOTE DOO YE ONE YE YE ER N-EYE-NE DR O YO DEED ED-ED ORR DY TO OO ED YRE RD-EH-YO (x) EY-T(x)E Y(x) NED YYTE DYEED Y(x) T DYEED YE D EDY YE ED ROY NE TODE O DYE RDY O D ND(x) . . ."

Again, the plain text reads: "Need the net ready the Tr 500th(x)2Enter(x)Y note due the one 2 the ER 9 Dr O tho deed 2 Ed Orr 500th to 2 Ed Wire Radeo(x) 8th T(x)e-th(x) Ned Wyte died Y(x) T died the dedth the Ed Roth NE told O die ready o 500 ND(x) . . ."



There is still a ways to go, and most likely some tweaking to be done, but just thought you should know what track I am on.

I have not yet tried this on Cipher 3, nor do I believe that the presence of 1 cipher might exclude others in the same transmission. So, until the "fat lady" sings (no jokes about my pudgyness plaese) HAPPY HUNTING . . .
 

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bigscoop

Gold Member
Jun 4, 2010
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Wherever there be treasure!
Detector(s) used
Older blue Excal with full mods, Equinox 800.
Primary Interest:
All Treasure Hunting
Using code values 1 - 800, assign letters to each of the 800 codes and then at random scramble 500 of them however you like in similar cipher fashion. Now apply your same solution principles. What you will find is that you will end up with a similar type of solution clear text. Sorry, but what you have is a very common, "jargon solution". You can achieve this same thing simply by using the first or last letters of any ordinary page of text. In the end the result can be interpreted in similar fashion.
 

K

Kentucky Kache

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I have to agree with Bigscoop. It seems you're making up your own rules as to how to interpret the text. Doing that, you can make any text say anything you want it to say. But at least you're doing something, and I give you thumbs up for that.
 

Rebel - KGC

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Jun 15, 2007
21,680
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(WINK) ACA; American Cryptogram Association, eh? VERTICAL? LAWD GAWD A'MIGHTY! Going to the annual convention, in Denver? Keep us posted! THANKS! (SHADES ON...)
 

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