Thanks for the insight. I found the link to Littleton's website. Assuming the min. thickness of 0.007 mils to qualify as gold electroplate, and ignoring surface features and reeding, which act to somewhat increase effective surface area, and ignoring coin wear, which acts to reduce surface area, and ignoring the effects of curvature on volume, and assuming a uniform coating and standard coin size with no variation from the coin's official specifications, and assuming 24k gold, since we know the coin's diameter is 30.6 mm, and it's thickness is 2.15 mm, and 0.007 mils = 0.0001778 mm, then the volume of gold is 0.0001778*(2*pi*(30.6/2)^2 + pi*30.6*2.15) = 0.298 mm^3. Since gold's specific gravity is 19.32 g/cm^3 = 0.01932 g/mm^3, the mass of gold is 0.298*0.01932 = 0.005762 g Au. Since there are 31.1034768 g/oz t, there are 0.005762/31.1034768 = 0.000185 oz t, with a current market value, since gold is trading for $1,121.80/oz t, of 0.000185*1121.8 = $0.207816, or 20.7816 cents.
with a current market value, since gold is trading for $1,121.80/oz t, of 0.000185*1121.8 = $0.207816, or 20.7816 cents.