Gold toned 1974 Kennedy

[Jyorsky]

Got this today in mr...any ideas...gold toned

 

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[Avago]

Electroplated in the thinnest layer of gold you can imagine, probably just a few microns... I think I did the math one time. There were a few cents worth of gold on one of them.

Unscrupulous coin companies have been known to market these to unwitting coin collectors for a hefty premium. Actual value? Face.

For instance, a not-so-Little Coin Company is currently selling a 1964 Gold-Plated half dollar for no less than $35.45 (plus $6.95 shipping.) Worth no more than the $5.25 silver melt.

When I find them, I mark them so nobody else can try to take advantage by re-selling.

 

[Jyorsky]

Well said and Ty for advice

 

[Cobbolicious]

Thanks for the insight. I found the link to Littleton's website. Assuming the min. thickness of 0.007 mils to qualify as gold electroplate, and ignoring surface features and reeding, which act to somewhat increase effective surface area, and ignoring coin wear, which acts to reduce surface area, and ignoring the effects of curvature on volume, and assuming a uniform coating and standard coin size with no variation from the coin's official specifications, and assuming 24k gold, since we know the coin's diameter is 30.6 mm, and its thickness is 2.15 mm, and 0.007 mils = 0.0001778 mm, then the volume of gold is 0.0001778*(2*pi*(30.6/2)^2 + pi*30.6*2.15) = 0.298 mm^3. Since gold's specific gravity is 19.32 g/cm^3 = 0.01932 g/mm^3, the mass of gold is 0.298*0.01932 = 0.005762 g Au. Since there are 31.1034768 g/oz t, there are 0.005762/31.1034768 = 0.000185 oz t, with a current market value, since gold is trading for $1,121.80/oz t, of 0.000185*1121.8 = $0.207816, or 20.7816 cents.

 

[weighit]

I find them quite often in the boxes I go through and give them away as tips when we eat out. Other than being different they to me have no added value.

 

[BigWaveDave]

Thanks for the insight. I found the link to Littleton's website. Assuming the min. thickness of 0.007 mils to qualify as gold electroplate, and ignoring surface features and reeding, which act to somewhat increase effective surface area, and ignoring coin wear, which acts to reduce surface area, and ignoring the effects of curvature on volume, and assuming a uniform coating and standard coin size with no variation from the coin's official specifications, and assuming 24k gold, since we know the coin's diameter is 30.6 mm, and it's thickness is 2.15 mm, and 0.007 mils = 0.0001778 mm, then the volume of gold is 0.0001778*(2*pi*(30.6/2)^2 + pi*30.6*2.15) = 0.298 mm^3. Since gold's specific gravity is 19.32 g/cm^3 = 0.01932 g/mm^3, the mass of gold is 0.298*0.01932 = 0.005762 g Au. Since there are 31.1034768 g/oz t, there are 0.005762/31.1034768 = 0.000185 oz t, with a current market value, since gold is trading for $1,121.80/oz t, of 0.000185*1121.8 = $0.207816, or 20.7816 cents.

Dude, your math is way off.... its more like 21.0781 cents.... you forgot to carry the 1

 

[norcalsteve]

I belong to a gold prospecting club and I donate them to the raffle.

 

[Avago]

with a current market value, since gold is trading for $1,121.80/oz t, of 0.000185*1121.8 = $0.207816, or 20.7816 cents.

So if you can accumulate 5,419 of these gold plated halves, with all of your assumptions in tact one ought be able to refine out an ozt of gold.

That's nearly five and a half solid boxes worth.