40% versus 90% Halves

[Quin]

Hey everyone,

I am currently working through a few calculations that I would like to to debut on my channel that have to do with the Kennedy 40% half dollar. I plan to propose a little math problem and offer a reward to the first person who can come up with the correct expression and use it to answer my question correctly.

Before I do this, I want to know from all of you- what is the ratio of 40% to 90% half dollars that you have found in all of your years coin roll hunting? I know that at least a few of you will have an exact number, but if you have to give an estimate that is okay too.

Thanks,
- Ryan

 

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[Quin]

Also, just a quick follow up question...does anybody know, when we are talking about 40% or 90% silver, is that percentage by mass or by volume? I am almost certain it is by mass but I just want to make sure.

 

[CoinFetcher]

It's by mass.

10 to 1 - 40% to 90% - about that.

Nothing in gold silver or metals or coins is done calculated. By 'volume'. It's all by weight. (Or mass as you like to say)

 

[Quin]

It's by mass.

10 to 1 - 40% to 90% - about that.

Nothing in gold silver or metals or coins is done calculated. By 'volume'. It's all by weight. (Or mass as you like to say)

Geez 10 to 1...that's higher than I was expecting. I am at 7 to 1 right now. And that's what I suspected, thanks for the clarification!

 

[weighit]

I've been collecting CRH since 1998 and can only guess that I find at least 10 40% to 1 90% coin. I never sell the 90% but have sold $210 in 40% and still have a boat load of 40% coin rolls in the box.

 

[port ewen ace]

$110K searched--79/90%
328/40%
the anomaly here is that 2 boxes had 49 Walkers. there goes the ratio

 

[goldencoin]

1 40% for every $90 and 1 90% for every $361 searched. and overall 4:1 40% to 90%. From past 8 years mostly CWR

HH
-GC

 

[LooseChange]

I have a guess on the math problem:

Predict the number of 40% halves, 90% halves, and clad halves in a pile of coins based on the total weight of the pile.

That would be a 3 equation, 3 unknown math problem.

3 unknowns:
F is number of forties; N is number of nineties, C is number of clads.

First equation:
F + N + C = TOTAL NUMBER OF COINS

Second equation:
F = 6.3*N (that there are either 4, 7 or 10 40's for every 90 - based on reports here. 6.3 is the equally weighted blending of those ratios.)

Third equation:
11.5*F + 12.5*N + 11.34*C = [TOTAL WEIGHT of COINS] (40's weigh 11.5g, 90's weight 12.5, and clads weigh 11.34).

Solving for F, N, and C is pretty easy using substitution.

 

[Quin]

I have a guess on the math problem:

Predict the number of 40% halves, 90% halves, and clad halves in a pile of coins based on the total weight of the pile.

That would be a 3 equation, 3 unknown math problem.

3 unknowns:
F is number of forties; N is number of nineties, C is number of clads.

First equation:
F + N + C = TOTAL NUMBER OF COINS

Second equation:
F = 6.3*N (that there are either 4, 7 or 10 40's for every 90 - based on reports here. 6.3 is the equally weighted blending of those ratios.)

Third equation:
11.5*F + 12.5*N + 11.34*C = [TOTAL WEIGHT of COINS] (40's weigh 11.5g, 90's weight 12.5, and clads weigh 11.34).

Solving for F, N, and C is pretty easy using substitution.

Good guess, but not quite! The data that I gather from this post will serve as a reason to convince you that the problem I present is actually worth consideration. So, it will not show up as a variable in the problem. The problem does have a lot to do with 40 percenters though. Also, the one that you just came up with is another good exercise (but I can't offer a reward for it because you've already got it down!) I might offer it as a warm-up, if you're okay with that? I'll give you credit of course.

I'm just trying to show my young subscribers that math really does come in handy in the real world. Unless it's discrete math, which I should be studying right now but instead I'm on Treasurenet. Yeah screw discrete math

 

[ArkieBassMan]

Its at least 20-1 40% to 90%. Probably closer to 30-1.

 

[Quin]

$110K searched--79/90%
328/40%
the anomaly here is that 2 boxes had 49 Walkers. there goes the ratio

Take out those walkers and you're right in there around the 10 to 1 mark!

 

[LooseChange]

... I might offer it as a warm-up, if you're okay with that? ...

Feel free to share it or adapt it in any shape or form - fully open source.

 

[Dozer D]

Change the coin subject ratio to dimes, and the ratio would likely be a 30-to-1 Rosie vs Merc. That's about what my dime fix is at.

 

[jcole77]

Right now, my ratio sits at 19 40%ers :7 90%ers... yes, I've been luckier than most so far...

 

[jcole77]

$110K searched--79/90%
328/40%
the anomaly here is that 2 boxes had 49 Walkers. there goes the ratio

That is good information... were there any 40%-ers or any other 90s in those two boxes?

When I post my nickel totals, my one month is so skewed because of the 1 almost full box (44 rolls) which produced 170 pre-60s...

 

[jcole77]

An interesting side note to the math problem... those of us who weigh our halves regularly know they usually weigh in the 224-225 gram range if they're all clad... Clads weigh 11.34 grams each, so a roll should weigh at least 226.8 grams. Are the planchets underweighted, or does wear account for this difference?

 

[ArkieBassMan]

An interesting side note to the math problem... those of us who weigh our halves regularly know they usually weigh in the 224-225 gram range if they're all clad... Clads weigh 11.34 grams each, so a roll should weigh at least 226.8 grams. Are the planchets underweighted, or does wear account for this difference?

I would guess some is wear, but I think it has to be mostly due to more being underweight than overweight to begin with. Out of curiosity, I weighed all of my MWR for a time. Not even with the added weight of the paper roll itself did I ever find a roll weighing 226.8+ that didn't contain a 90% silver or heavy foreign coin. Not one. Most of my all clad rolls came in 225.0 - 226.0.

I once had a roll weighing 225.4 that contained 2 40%ers, as well as many rolls in the 225's that contained 1 40%er. I had rolls weighing as much as 226.5 that contained no silver. If I remember correctly, I found more rolls containing 40% silver that weighed under 226g than over 226. This is why weighing the rolls/coins in lieu of searching is pretty much fruitless.

 

[jrf30]

For me, my last few years (Not my total, but I have them broken down by eons, as I call them) I have 1 Barber Half, 8 Walking Liberty, 49 Franklin, 3 Franklin Proof, 125 90% Kennedy, and 1,033 40% Kennedy Halves. PLus 2 statue of Liberty Commemoratives, 1 Canadian silver half, and 1 Panama silver Medio Balboa.

 

[FormerTeller]

I've kept spreadsheets of every roll searched since I started in 2011, and for me the average ratio is 4.8:1. The interesting thing is that the ratio has gone down over the years: I. 2012 it was 7.5:1, then 6:1 for a few years, then 5:1. 2015 was 4.3:1. Of course, number if silver per box has fallen over the years as well.

 

[FreedomUIC]

I hunted for a relatively short time compared to some on here, about six years total doing $1,500 a week.
When I first started the game the ratio was roughly 3.8 to 1 40% to 90%. This ratio was good until
everybody started bragging about it, posting YouTube video's on it and so on, I am not being mean, I am being honest.

The banks started hating us hunters/hobbyists because of all the advertisement going on. In the end of my CRH hobby
I averaged exactly 15.3 to 1 40% to 90% and that year was skewed because of a box that contained over 100 90%'ers, 102
to be exact so the ratio is even worst than 15.3 to 1 if you exclude that one box. You can search the archives's, I posted about
it here.