Re: Let's Talk Pennies
Ryedale said:
GMan00001 said:
Sheldius said:
Could you put a zincoln in the reference slot and have it "reject" the copper and brass coins? That way you don't have to sort twice. Just academic at this point, since I don't have either a source of pennies or a Ryedale.
That's exactly what I asked yesterday in a different thread.
You can do this but it tends to also reject unpure zinc, so your "coppers" tend to be contaminated with these zinc, it will also toss Canadian steel, Canadian zinc, and some other foreign coins. I've found the best process to be, copper keep, then if your not satisfied with the pile of copper you just got, switch to a zinc standard and re-process to get unpure previously rejected coppers (from the 70's only a few per hundred dollars face) and missed wheats (usually one or two per hundred dollars face) etc, that were "not copper" on the first pass. This process is taught in detail in the instructions. There is a
method to get nearly everything of value out of the bulk mixed coins. Dont forget, it is a copper mine first, and numismatic mine second.
I understand it will reject potentially other undesirables as well into the copper pile, but consider these two options.
Option 1:
Step 1) Choose the match as a pre-1982 copper penny.
Step 2) Sort the batch of pennies to take out the copper
Step 3) Choose the match as a zincoln penny (post 1982)
Step 4) Sort the first pass rejects to remove the zincolns.
Step 5) Sort through the copper by hand to remove the wheaties.
Step 6) Sort through the second pass rejects to find the older wheaties, foreign, or other keepers.
Option 2:
Step 1) Choose the match as a zincoln penny (post 1982)
Step 2) Sort the batch of pennies to remove the zincolns (guaranteed rejects)
Step 3) Choose the match as a pre-1982 copper penny.
Step 4) Sort the batch of original rejects to take out the copper
Step 5) Sort through the copper by hand to remove the wheaties.
Step 6) Sort through the second pass rejects to find the older wheaties, foreign, or other keepers.
For simplification, say you have 10,000 pennies and the breakdown of the pennies is the following:
zincolns 80%
coppers 19%
Other 1% (other is canadian, old wheaties, foreign, tokens, etc.)
So that would be
8000 zincolns
1900 coppers
100 other
For option 1
Result of step 2) Run all 10,000 pennies through the machine once (result is 1900 coppers, 8100 other)
Result of step 4) Run the 8,100 reject pennies from the first pass through the machine again (result is 8000 zincolns, 100 other)
Result of step 5) Hand sort 1,900 coppers to remove the wheaties.
Result of step 6) Hand sort 100 second pass rejects to remove any other keepers.
For option 2
Result of step 2) Run all 10,000 pennies through the machine once (result is 8000 zincolns, 2000 other)
Result of step 4) Run the 2,000 reject pennies from the first pass through the machine again (result is 1900 coppers, 100 other)
Result of step 5) Hand sort 1,900 coppers to remove the wheaties.
Result of step 6) Hand sort 100 second pass rejects to remove any other keepers.
Total coins run through the machine for option 1 = 18,100
Total coins run through the machine for option 2 = 12,000
Seems like quite a time savings as well as wear and tear on the machine. Now if the machine thinks a lot of copper pennies match the zincoln example I can see you point, but that would also defeat the whole point if the machine if that sorting mechanism did not work properly.
To your other point that you would end up with zincolns that didn't match the zincoln on pass 1 of option 2 because of composition issues in the zincolns. Unless that number is extremely high, you still would have quite a time and machine savings and your coppers would still be pure since you did a compare against coppers.
I guess it is true that it only applies to those who feel they need a second pass on the rejects. Anyone who says the first "copper" pass is good enough, this wouldn't help.